1. **State the problem:** Factor the expression $$p^{12}q^{2} - p^{3}q^{6}$$.
2. **Identify the greatest common factor (GCF):**
- For the powers of $p$, the smallest exponent is 3, so GCF for $p$ is $p^{3}$.
- For the powers of $q$, the smallest exponent is 2, so GCF for $q$ is $q^{2}$.
3. **Extract the GCF:**
$$p^{12}q^{2} - p^{3}q^{6} = p^{3}q^{2}(p^{12-3} - q^{6-2}) = p^{3}q^{2}(p^{9} - q^{4})$$
4. **Check if the remaining expression can be factored further:**
- The expression inside the parentheses is $$p^{9} - q^{4}$$.
- This is a difference of powers but not a simple difference of squares or cubes that factor nicely with integer exponents.
5. **Conclusion:** The factored form is $$p^{3}q^{2}(p^{9} - q^{4})$$.
**Final answer:** A. $$p^{3}q^{2}(p^{9} - q^{4})$$
Factoring Polynomial 255958
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