1. **State the problem:** Factorise the expression $$14y^2 + 14$$ completely. 2. **Identify the common factor:** Both terms have a common factor of 14. 3. **Apply the distributive property:** $$14y^2 + 14 = 14(y^2 + 1)$$ 4. **Check if further factorisation is possible:** The expression inside the parentheses, $$y^2 + 1$$, is a sum of squares, which cannot be factorised further over the real numbers. 5. **Final answer:** $$14(y^2 + 1)$$ This is the complete factorisation of the given expression.