Subjects algebra

Factors Of 243

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1. The problem is to find two numbers that multiply together to give 243. 2. We start by factoring 243 into its prime factors. Since 243 is a power of 3, we can write: $$243 = 3^5$$ 3. Now, to find two numbers that multiply to 243, we can split the exponent 5 into two parts, say $a$ and $b$, such that: $$a + b = 5$$ and the two numbers are: $$3^a \text{ and } 3^b$$ 4. For example, if $a=2$ and $b=3$, then the two numbers are: $$3^2 = 9 \quad \text{and} \quad 3^3 = 27$$ 5. Multiplying these two numbers: $$9 \times 27 = 243$$ 6. Therefore, one pair of numbers that multiply to 243 is 9 and 27. 7. Other pairs can be found by choosing different values of $a$ and $b$ such as $a=1$, $b=4$ giving $3$ and $81$, or $a=0$, $b=5$ giving $1$ and $243$. Final answer: Two numbers that multiply to 243 can be 9 and 27.