Subjects algebra

Fare Table 1582F9

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1. **State the problem:** We are given a fare rule for a taxi fare: $$\text{Fare} = 2 + 0.5d$$ where $d$ is the distance in kilometers. We need to complete the fare table for given distances. 2. **Formula and explanation:** The fare consists of a base fare of 2 plus 0.5 times the distance traveled. This means for every kilometer, 0.5 is added to the base fare. 3. **Calculate fare for each distance:** - For $d=0$: $$\text{Fare} = 2 + 0.5 \times 0 = 2 + 0 = 2$$ - For $d=2$: $$\text{Fare} = 2 + 0.5 \times 2 = 2 + 1 = 3$$ - For $d=4$: $$\text{Fare} = 2 + 0.5 \times 4 = 2 + 2 = 4$$ - For $d=6$: $$\text{Fare} = 2 + 0.5 \times 6 = 2 + 3 = 5$$ - For $d=8$: $$\text{Fare} = 2 + 0.5 \times 8 = 2 + 4 = 6$$ - For $d=10$: $$\text{Fare} = 2 + 0.5 \times 10 = 2 + 5 = 7$$ 4. **Variables and meaning:** - Independent variable (input): distance $d$ in kilometers - Dependent variable (output): fare 5. **Rule in words:** Start with a base fare of 2, then add 0.5 for every kilometer traveled. **Final completed table:** | $d$ (km) | Fare | |---|---| | 0 | 2 | | 2 | 3 | | 4 | 4 | | 6 | 5 | | 8 | 6 | | 10 | 7 |