1. **Problem:** A farmer wants to build a rectangular fence around a garden. The length of the garden is 10 meters more than its width. If the farmer has 60 meters of fencing material, what are the dimensions of the garden? 2. **Formula:** The perimeter $P$ of a rectangle is given by $P = 2(l + w)$ where $l$ is length and $w$ is width. 3. **Step 1:** Let the width be $w$ meters. Then the length is $l = w + 10$. 4. **Step 2:** Using the perimeter formula: $$60 = 2((w + 10) + w)$$ 5. **Step 3:** Simplify inside the parentheses: $$60 = 2(2w + 10)$$ 6. **Step 4:** Distribute the 2: $$60 = 4w + 20$$ 7. **Step 5:** Subtract 20 from both sides: $$60 - 20 = 4w + \cancel{20} - 20$$ $$40 = 4w$$ 8. **Step 6:** Divide both sides by 4: $$\frac{40}{\cancel{4}} = \frac{4w}{\cancel{4}}$$ $$10 = w$$ 9. **Step 7:** Find length: $$l = w + 10 = 10 + 10 = 20$$ **Answer:** The width is 10 meters and the length is 20 meters.