1. **State the problem:** We have a rectangular parking lot enclosed by a fence of length 110 meters. The length of the parking lot is 5 meters more than its width. We need to find the length and width. 2. **Formula used:** The perimeter $P$ of a rectangle is given by $$P = 2(\text{length} + \text{width})$$ 3. **Set variables:** Let the width be $w$ meters. Then the length is $w + 5$ meters. 4. **Write the perimeter equation:** $$110 = 2(w + (w + 5))$$ 5. **Simplify the equation:** $$110 = 2(2w + 5) = 4w + 10$$ 6. **Solve for $w$:** $$4w + 10 = 110$$ $$4w = 110 - 10 = 100$$ $$w = \frac{100}{4} = 25$$ 7. **Find the length:** $$\text{length} = w + 5 = 25 + 5 = 30$$ 8. **Answer:** The width is 25 meters and the length is 30 meters.