1. **Problem:** Find the sixteenth term of a Fibonacci sequence whose first two terms are -3 and 9. 2. **Formula and rules:** In a Fibonacci sequence, each term after the first two is the sum of the two preceding terms. 3. **Step-by-step solution:** - Given: $F_1 = -3$, $F_2 = 9$ - Calculate subsequent terms: $F_3 = F_1 + F_2 = -3 + 9 = 6$ $F_4 = F_2 + F_3 = 9 + 6 = 15$ $F_5 = F_3 + F_4 = 6 + 15 = 21$ $F_6 = F_4 + F_5 = 15 + 21 = 36$ $F_7 = F_5 + F_6 = 21 + 36 = 57$ $F_8 = F_6 + F_7 = 36 + 57 = 93$ $F_9 = F_7 + F_8 = 57 + 93 = 150$ $F_{10} = F_8 + F_9 = 93 + 150 = 243$ $F_{11} = F_9 + F_{10} = 150 + 243 = 393$ $F_{12} = F_{10} + F_{11} = 243 + 393 = 636$ $F_{13} = F_{11} + F_{12} = 393 + 636 = 1029$ $F_{14} = F_{12} + F_{13} = 636 + 1029 = 1665$ $F_{15} = F_{13} + F_{14} = 1029 + 1665 = 2694$ $F_{16} = F_{14} + F_{15} = 1665 + 2694 = 4359$ 4. **Answer:** The sixteenth term of the Fibonacci sequence is **4359**.