1. The vertex of a parabola given by the quadratic function $y = ax^2 + bx + c$ is found using the formula for the $x$-coordinate of the vertex: $$x = -\frac{b}{2a}$$ 2. Once you find the $x$-coordinate, substitute it back into the original quadratic equation to find the $y$-coordinate of the vertex. 3. The vertex is then the point $$\left(-\frac{b}{2a}, y\left(-\frac{b}{2a}\right)\right)$$. 4. This point represents the maximum or minimum of the parabola depending on the sign of $a$: if $a > 0$, the vertex is a minimum; if $a < 0$, the vertex is a maximum. 5. If you provide the specific quadratic function, I can calculate the exact vertex for you.