1. **State the problem:** Given the equation where $y=14$ when $x=5$, find $x$ when $y=28$. 2. **Identify the relationship:** Since $y$ changes with $x$, assume a direct proportionality: $y = kx$ where $k$ is a constant. 3. **Find the constant $k$:** Using the known values, $$14 = k \times 5$$ Divide both sides by 5: $$k = \frac{14}{5}$$ 4. **Use $k$ to find $x$ when $y=28$:** $$28 = \frac{14}{5} \times x$$ Divide both sides by $\frac{14}{5}$: $$x = \frac{28}{\frac{14}{5}}$$ Rewrite division as multiplication by reciprocal: $$x = 28 \times \frac{5}{14}$$ Simplify: $$x = \cancel{28} \times \frac{5}{\cancel{14}} = 2 \times 5 = 10$$ 5. **Final answer:** When $y=28$, $x=10$.