1. The problem is to find the values of $y$ corresponding to $x=0$ and $x=2$ using the given equations. 2. The equations given are: $$y = \frac{1}{3} \times 0$$ $$y = \frac{1}{2} \times 2$$ 3. Calculate $y$ when $x=0$: $$y = \frac{1}{3} \times 0 = 0$$ 4. Calculate $y$ when $x=2$: $$y = \frac{1}{2} \times 2 = \cancel{\frac{1}{2}} \times \cancel{2} = 1$$ 5. So, the values are: - When $x=0$, $y=0$ - When $x=2$, $y=1$ 6. These calculations show how to substitute values of $x$ into linear equations to find corresponding $y$ values.