1. **State the problem:** We are given a cubic function $$f(x) = x^3 - 14x^2 + 61x - 84$$ and told that one factor is $$(x - 7)$$. We need to find all zeros of the function. 2. **Use the factor theorem:** Since $$(x - 7)$$ is a factor, $$x = 7$$ is a root of the polynomial. 3. **Divide the polynomial by $$(x - 7)$$:** Use polynomial division or synthetic division to find the quotient polynomial. Using synthetic division: $$\begin{array}{r|rrrr} 7 & 1 & -14 & 61 & -84 \\ & & 7 & -49 & 84 \\ \hline & 1 & -7 & 12 & 0 \\ \end{array}$$ The quotient is $$x^2 - 7x + 12$$. 4. **Factor the quadratic:** $$x^2 - 7x + 12 = (x - 3)(x - 4)$$ 5. **Find zeros:** The zeros are the roots of each factor: $$x - 7 = 0 \Rightarrow x = 7$$ $$x - 3 = 0 \Rightarrow x = 3$$ $$x - 4 = 0 \Rightarrow x = 4$$ 6. **Final answer:** The zeros of the function are $$7, 3, 4$$. **Answer choice:** 7, 4, 3 (order does not matter)