1. **Stating the problem:** We need to find the first term of the expression $\left(\frac{16}{9} \times \left(-\frac{3}{2}\right)\right)^6$. 2. **Understanding the expression:** The expression inside the parentheses is $\frac{16}{9} \times \left(-\frac{3}{2}\right)$, and this entire product is raised to the power 6. 3. **Calculate the product inside the parentheses:** $$\frac{16}{9} \times \left(-\frac{3}{2}\right) = \frac{16 \times (-3)}{9 \times 2} = \frac{-48}{18}$$ 4. **Simplify the fraction:** $$\frac{-48}{18} = \frac{\cancel{-48}}{\cancel{18}} = \frac{-48 \div 6}{18 \div 6} = \frac{-8}{3}$$ 5. **Rewrite the expression:** $$\left(\frac{-8}{3}\right)^6$$ 6. **Calculate the first term:** Since the expression is a single term raised to a power, the "first term" is the expression itself before expansion, which is $\frac{-8}{3}$. **Final answer:** The first term is $\frac{-8}{3}$.