1. **State the problem:** Patrick, Marcel, Anthony, and Yannick caught 35 fishes in total. Marcel caught three times as many fishes as Yannick. Patrick caught three more fishes than Marcel. Anthony caught 8 more fishes than Yannick. We need to find how many fishes Anthony caught. 2. **Define variables:** Let $Y$ be the number of fishes Yannick caught. 3. **Express others in terms of $Y$:** - Marcel caught $3Y$ fishes. - Patrick caught $3Y + 3$ fishes. - Anthony caught $Y + 8$ fishes. 4. **Write the total fishes equation:** $$Y + 3Y + (3Y + 3) + (Y + 8) = 35$$ 5. **Simplify the equation:** $$Y + 3Y + 3Y + 3 + Y + 8 = 35$$ $$8Y + 11 = 35$$ 6. **Isolate $Y$:** $$8Y = 35 - 11$$ $$8Y = 24$$ 7. **Solve for $Y$:** $$Y = \frac{24}{8}$$ $$Y = 3$$ 8. **Find Anthony's fishes:** $$Y + 8 = 3 + 8 = 11$$ **Answer:** Anthony caught 11 fishes.