1. **State the problem:** We need to find 5 positive whole numbers in ascending order such that: - The median is 9 - The mode is 6 - The range is 11 - The mean is 10 2. **Define variables:** Let the numbers be $a \leq b \leq c \leq d \leq e$. 3. **Use the median condition:** The median of 5 numbers is the 3rd number, so: $$c = 9$$ 4. **Use the mode condition:** The mode is 6, so 6 must appear more times than any other number. Since the numbers are positive whole numbers and sorted, 6 must appear at least twice. 5. **Use the range condition:** The range is $e - a = 11$. 6. **Use the mean condition:** The mean is 10, so the sum is: $$a + b + c + d + e = 5 \times 10 = 50$$ 7. **Assign the mode 6:** Since 6 is the mode and must appear at least twice, and numbers are sorted, the smallest two numbers are likely 6: $$a = 6, b = 6$$ 8. **Substitute known values:** $$6 + 6 + 9 + d + e = 50$$ $$21 + d + e = 50$$ $$d + e = 29$$ 9. **Use the range:** $$e - a = 11 \Rightarrow e - 6 = 11 \Rightarrow e = 17$$ 10. **Find $d$:** $$d + 17 = 29 \Rightarrow d = 12$$ 11. **Check order:** $$6 \leq 6 \leq 9 \leq 12 \leq 17$$ 12. **Check mode:** 6 appears twice, others appear once, so mode is 6. 13. **Check median:** 3rd number is 9. 14. **Check range:** $17 - 6 = 11$. 15. **Check mean:** $(6 + 6 + 9 + 12 + 17)/5 = 50/5 = 10$. All conditions are satisfied. **Final answer:** $[6, 6, 9, 12, 17]$