1. **Problem 1:** Solve the equation $[x] + x + [x] = 1$, where $[x]$ denotes the floor function (greatest integer less than or equal to $x$).
2. **Step 1:** Let $n = [x]$, then the equation becomes $n + x + n = 1$ or $2n + x = 1$.
3. **Step 2:** Since $n = [x]$, we have $n \leq x < n+1$.
4. **Step 3:** Substitute $x = 1 - 2n$ from the equation into the inequality:
$$n \leq 1 - 2n < n + 1$$
5. **Step 4:** Solve the inequalities:
- Left: $n \leq 1 - 2n \Rightarrow 3n \leq 1 \Rightarrow n \leq \frac{1}{3}$
- Right: $1 - 2n < n + 1 \Rightarrow -2n < n \Rightarrow -3n < 0 \Rightarrow n > 0$
6. **Step 5:** Since $n$ is an integer, $0 < n \leq \frac{1}{3}$ implies $n = 0$.
7. **Step 6:** For $n=0$, $x = 1 - 2(0) = 1$ and check $[1] + 1 + [1] = 1 + 1 + 1 = 3 \neq 1$, so no solution here.
8. **Step 7:** Check $n=0$ carefully: $n=0$ means $0 \leq x < 1$, but $x=1$ is not in $[0,1)$, so no solution.
9. **Step 8:** Try $n=0$ with $x$ in $[0,1)$, then $x = 1 - 2(0) = 1$ is outside the interval, so no solution.
10. **Step 9:** Try $n=1$:
- Check inequalities: $1 \leq 1 - 2(1) = -1 < 2$ is false.
11. **Step 10:** Try $n=-1$:
- $-1 \leq 1 - 2(-1) = 3 < 0$ is false.
12. **Step 11:** No integer $n$ satisfies the inequalities, so no solution for problem 1.
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13. **Problem 2:** Solve $|x-1| + |x-1| = 3$.
14. **Step 1:** Simplify: $2|x-1| = 3 \Rightarrow |x-1| = \frac{3}{2}$.
15. **Step 2:** Solve absolute value:
$$x - 1 = \frac{3}{2} \quad \text{or} \quad x - 1 = -\frac{3}{2}$$
16. **Step 3:** Solutions:
$$x = 1 + \frac{3}{2} = \frac{5}{2}$$
$$x = 1 - \frac{3}{2} = -\frac{1}{2}$$
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17. **Problem 3:** Given sets $C = \{1, 2\}$, $B = \{2, 3\}$, $A = \{1, 2, 3\}$, and $M = \{1, ..., 1\}$ (likely a typo or singleton set $\{1\}$), find:
- $A \times B$ (Cartesian product)
- $(A - B) \cap C$
18. **Step 1:** Compute $A \times B$:
$$A \times B = \{(1,2), (1,3), (2,2), (2,3), (3,2), (3,3)\}$$
19. **Step 2:** Compute $A - B$ (elements in $A$ not in $B$):
$$A - B = \{1\}$$
20. **Step 3:** Compute $(A - B) \cap C$:
$$\{1\} \cap \{1, 2\} = \{1\}$$
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**Final answers:**
- Problem 1: No solution.
- Problem 2: $x = \frac{5}{2}$ or $x = -\frac{1}{2}$.
- Problem 3:
- $A \times B = \{(1,2), (1,3), (2,2), (2,3), (3,2), (3,3)\}$
- $(A - B) \cap C = \{1\}$
Floor Absolute Sets
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