Subjects algebra

Flower Equations 34951B

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1. **State the problem:** We have four equations involving flower values: - Pink flower \(p\) times pink flower \(p\) equals 9: \(p \times p = 9\). - \((p + o)^2 = 25\), where \(o\) is orange flower. - \(p + o - (p - o) = r\), where \(r\) is red flower. - Find \(p + r \times r - o\). 2. **Use the formulas and rules:** - From \(p \times p = 9\), we get \(p^2 = 9\). - From \((p + o)^2 = 25\), expand using \((a+b)^2 = a^2 + 2ab + b^2\). - Simplify the third equation. 3. **Solve for \(p\):** $$p^2 = 9$$ Taking square root: $$p = \pm 3$$ 4. **Solve for \(p + o\):** $$ (p + o)^2 = 25 $$ Taking square root: $$ p + o = \pm 5 $$ 5. **Simplify the third equation:** $$ p + o - (p - o) = r $$ Distribute the minus: $$ p + o - p + o = r $$ Simplify: $$ 2o = r $$ 6. **Express \(r\) in terms of \(o\):** $$ r = 2o $$ 7. **Find \(p + r \times r - o\):** Substitute \(r = 2o\): $$ p + (2o) \times (2o) - o = p + 4o^2 - o $$ 8. **Use \(p + o = \pm 5\) to express \(o\) in terms of \(p\):** $$ o = \pm 5 - p $$ 9. **Try \(p = 3\) and \(p + o = 5\) (positive roots):** $$ o = 5 - 3 = 2 $$ $$ r = 2o = 4 $$ 10. **Calculate the expression:** $$ p + r \times r - o = 3 + 4 \times 4 - 2 = 3 + 16 - 2 = 17 $$ 11. **Check other root combinations:** - If \(p = -3\) and \(p + o = -5\), then \(o = -5 - (-3) = -2\), \(r = 2(-2) = -4\), expression: $$ -3 + (-4) \times (-4) - (-2) = -3 + 16 + 2 = 15 $$ - If \(p = 3\) and \(p + o = -5\), then \(o = -5 - 3 = -8\), \(r = 2(-8) = -16\), expression: $$ 3 + (-16) \times (-16) - (-8) = 3 + 256 + 8 = 267 $$ - If \(p = -3\) and \(p + o = 5\), then \(o = 5 - (-3) = 8\), \(r = 2(8) = 16\), expression: $$ -3 + 16 \times 16 - 8 = -3 + 256 - 8 = 245 $$ 12. **Choose the most reasonable positive solution:** \(p = 3\), \(o = 2\), \(r = 4\), expression value = 17. **Final answer:** $$\boxed{17}$$