Subjects algebra

Flower Equations 7Aa223

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1. **State the problem:** We have the following equations with flower symbols representing variables: - Flower \( \times \) Flower = 9 - \( (\text{Flower} + \text{Tulip})^2 = 25 \) - \( \text{Flower} + \text{Tulip} - (\text{Flower} - \text{Tulip}) = \text{Rose} \) - Find the value of \( \text{Flower} + \text{Rose} \times \text{Rose} - \text{Tulip} \). 2. **Identify variables:** Let \( F = \text{Flower} \), \( T = \text{Tulip} \), \( R = \text{Rose} \). 3. **From the first equation:** $$ F \times F = 9 \implies F^2 = 9 $$ Taking the positive root (assuming positive values for flowers): $$ F = 3 $$ 4. **From the second equation:** $$ (F + T)^2 = 25 $$ Taking the square root: $$ F + T = \pm 5 $$ Since \( F = 3 \), $$ 3 + T = \pm 5 $$ Two cases: - Case 1: \( 3 + T = 5 \implies T = 2 \) - Case 2: \( 3 + T = -5 \implies T = -8 \) 5. **From the third equation:** $$ F + T - (F - T) = R $$ Simplify inside the parentheses: $$ F + T - F + T = R $$ $$ (F - F) + (T + T) = R $$ $$ 0 + 2T = R $$ $$ R = 2T $$ 6. **Calculate the expression:** $$ F + R \times R - T $$ Substitute \( R = 2T \): $$ F + (2T)^2 - T = F + 4T^2 - T $$ 7. **Evaluate for each case:** - Case 1: \( T = 2 \) $$ F + 4(2)^2 - 2 = 3 + 4 \times 4 - 2 = 3 + 16 - 2 = 17 $$ - Case 2: \( T = -8 \) $$ F + 4(-8)^2 - (-8) = 3 + 4 \times 64 + 8 = 3 + 256 + 8 = 267 $$ 8. **Conclusion:** The problem does not specify the sign of \( T \), but typically positive values are preferred for flower counts. Thus, the most reasonable answer is: $$ \boxed{17} $$