1. **State the problem:**
We have the following equations with flower symbols representing variables:
- Flower \( \times \) Flower = 9
- \( (\text{Flower} + \text{Tulip})^2 = 25 \)
- \( \text{Flower} + \text{Tulip} - (\text{Flower} - \text{Tulip}) = \text{Rose} \)
- Find the value of \( \text{Flower} + \text{Rose} \times \text{Rose} - \text{Tulip} \).
2. **Identify variables:**
Let \( F = \text{Flower} \), \( T = \text{Tulip} \), \( R = \text{Rose} \).
3. **From the first equation:**
$$ F \times F = 9 \implies F^2 = 9 $$
Taking the positive root (assuming positive values for flowers):
$$ F = 3 $$
4. **From the second equation:**
$$ (F + T)^2 = 25 $$
Taking the square root:
$$ F + T = \pm 5 $$
Since \( F = 3 \),
$$ 3 + T = \pm 5 $$
Two cases:
- Case 1: \( 3 + T = 5 \implies T = 2 \)
- Case 2: \( 3 + T = -5 \implies T = -8 \)
5. **From the third equation:**
$$ F + T - (F - T) = R $$
Simplify inside the parentheses:
$$ F + T - F + T = R $$
$$ (F - F) + (T + T) = R $$
$$ 0 + 2T = R $$
$$ R = 2T $$
6. **Calculate the expression:**
$$ F + R \times R - T $$
Substitute \( R = 2T \):
$$ F + (2T)^2 - T = F + 4T^2 - T $$
7. **Evaluate for each case:**
- Case 1: \( T = 2 \)
$$ F + 4(2)^2 - 2 = 3 + 4 \times 4 - 2 = 3 + 16 - 2 = 17 $$
- Case 2: \( T = -8 \)
$$ F + 4(-8)^2 - (-8) = 3 + 4 \times 64 + 8 = 3 + 256 + 8 = 267 $$
8. **Conclusion:**
The problem does not specify the sign of \( T \), but typically positive values are preferred for flower counts.
Thus, the most reasonable answer is:
$$ \boxed{17} $$
Flower Equations 7Aa223
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