Subjects algebra

Formula N 02Ebed

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1. **Stating the problem:** We are given the formula for $N$ as $$N = \frac{6000}{5p + z}$$ where $p$ and $z$ are variables. 2. **Understanding the formula:** This formula shows that $N$ is inversely proportional to the expression $5p + z$. As $5p + z$ increases, $N$ decreases, and vice versa. 3. **Important rules:** - Division by zero is undefined, so $5p + z \neq 0$. - To simplify or evaluate $N$, substitute values for $p$ and $z$ into the denominator. 4. **Example evaluation:** Suppose $p = 2$ and $z = 10$, then $$5p + z = 5 \times 2 + 10 = 10 + 10 = 20$$ 5. **Calculate $N$ with these values:** $$N = \frac{6000}{20}$$ 6. **Simplify the fraction:** $$N = 300$$ 7. **Summary:** The value of $N$ depends on the values of $p$ and $z$ through the denominator $5p + z$. To find $N$, plug in values for $p$ and $z$, compute the denominator, and divide 6000 by that result.