1. **State the problem:** We are given that 25 states have four-star hotels out of a total of 50 states. We need to find:
(a) The fraction of states with at least one four-star hotel.
(b) The number of states without a four-star hotel.
(c) The fraction of states without a four-star hotel.
2. **Formula and rules:**
- Fraction of states with four-star hotels = \frac{\text{number of states with hotels}}{\text{total number of states}}.
- Number of states without hotels = total states - states with hotels.
- Fraction of states without hotels = \frac{\text{number of states without hotels}}{\text{total number of states}}.
3. **Calculate fraction of states with four-star hotels:**
$$\frac{25}{50}$$
Simplify by dividing numerator and denominator by 25:
$$\frac{\cancel{25}}{\cancel{50}} = \frac{1}{2}$$
So, the fraction is $\frac{1}{2}$.
4. **Calculate number of states without four-star hotels:**
$$50 - 25 = 25$$
So, 25 states do not have a four-star hotel.
5. **Calculate fraction of states without four-star hotels:**
$$\frac{25}{50}$$
Simplify by dividing numerator and denominator by 25:
$$\frac{\cancel{25}}{\cancel{50}} = \frac{1}{2}$$
So, the fraction is $\frac{1}{2}$.
**Final answers:**
(a) $\frac{1}{2}$
(b) 25 states
(c) $\frac{1}{2}$
Four Star Hotels 25Fed5
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.