1. The problem is to evaluate the expression $\frac{3}{8} - \left(-\frac{1}{12}\right)$.\n\n2. When subtracting a negative number, it is equivalent to adding the positive of that number. So, the expression becomes:\n$$\frac{3}{8} + \frac{1}{12}$$\n\n3. To add these fractions, find a common denominator. The denominators are 8 and 12. The least common denominator (LCD) is 24.\n\n4. Convert each fraction to have denominator 24:\n$$\frac{3}{8} = \frac{3 \times 3}{8 \times 3} = \frac{9}{24}$$\n$$\frac{1}{12} = \frac{1 \times 2}{12 \times 2} = \frac{2}{24}$$\n\n5. Now add the fractions:\n$$\frac{9}{24} + \frac{2}{24} = \frac{9 + 2}{24} = \frac{11}{24}$$\n\n6. The final answer is:\n$$\frac{11}{24}$$