1. **State the problem:** Calculate the sum of the fractions $\frac{2}{-9} + \frac{-8}{9}$ and $\frac{9}{32} - \frac{-5}{-8}$.\n\n2. **Calculate the first expression:** $\frac{2}{-9} + \frac{-8}{9}$.\n- Rewrite as $-\frac{2}{9} + (-\frac{8}{9})$ because $\frac{2}{-9} = -\frac{2}{9}$.\n- Since denominators are the same, add numerators: $-2 + (-8) = -10$.\n- So, $-\frac{2}{9} + (-\frac{8}{9}) = \frac{-10}{9}$.\n\n3. **Calculate the second expression:** $\frac{9}{32} - \frac{-5}{-8}$.\n- Note that $\frac{-5}{-8} = \frac{5}{8}$ because negative signs cancel.\n- So, $\frac{9}{32} - \frac{5}{8}$.\n- Find common denominator: $32$ is common denominator since $8 \times 4 = 32$.\n- Rewrite $\frac{5}{8} = \frac{5 \times 4}{8 \times 4} = \frac{20}{32}$.\n- Now subtract: $\frac{9}{32} - \frac{20}{32} = \frac{9 - 20}{32} = \frac{-11}{32}$.\n\n4. **Final answers:**\n- $\frac{2}{-9} + \frac{-8}{9} = \frac{-10}{9}$.\n- $\frac{9}{32} - \frac{-5}{-8} = \frac{-11}{32}$.