1. **State the problem:** Simplify the expression $$\frac{8}{4x + 3} + \frac{5}{6x + 1}$$ leaving denominators factorized when possible.
2. **Find the common denominator:** The denominators are $4x + 3$ and $6x + 1$. Since they cannot be factored further, the common denominator is their product:
$$ (4x + 3)(6x + 1) $$
3. **Rewrite each fraction with the common denominator:**
$$ \frac{8}{4x + 3} = \frac{8(6x + 1)}{(4x + 3)(6x + 1)} $$
$$ \frac{5}{6x + 1} = \frac{5(4x + 3)}{(6x + 1)(4x + 3)} $$
4. **Add the numerators:**
$$ \frac{8(6x + 1) + 5(4x + 3)}{(4x + 3)(6x + 1)} $$
5. **Expand the numerators:**
$$ 8(6x + 1) = 48x + 8 $$
$$ 5(4x + 3) = 20x + 15 $$
6. **Sum the expanded numerators:**
$$ 48x + 8 + 20x + 15 = (48x + 20x) + (8 + 15) = 68x + 23 $$
7. **Final simplified expression:**
$$ \frac{68x + 23}{(4x + 3)(6x + 1)} $$
This is the simplified form with the denominator factorized as requested.
Fraction Addition E95183
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