1. The problem is to compare the two fractions $\frac{11}{3}$ and $\frac{47}{13}$ and determine the correct comparison operator ($>$, $<$, or $=$) to place between them. 2. To compare fractions, we can cross-multiply and compare the products. 3. Cross-multiply: $$11 \times 13 = 143$$ $$47 \times 3 = 141$$ 4. Since $143 > 141$, it means: $$\frac{11}{3} > \frac{47}{13}$$ 5. Therefore, the correct comparison operator to place in the box is $>$. This means $\frac{11}{3}$ is greater than $\frac{47}{13}$.