1. **State the problem:** Compare the fractions $1 \frac{1}{2}$, $\frac{3}{2}$, and $\frac{17}{6}$ using $<$, $>$, or $=$. 2. **Convert mixed fractions to improper fractions:** - $1 \frac{1}{2} = \frac{2 \times 1 + 1}{2} = \frac{3}{2}$ 3. **Rewrite the comparison:** - Compare $\frac{3}{2}$ and $\frac{17}{6}$. 4. **Find a common denominator:** - The denominators are 2 and 6. The least common denominator (LCD) is 6. - Convert $\frac{3}{2}$ to sixths: $\frac{3}{2} = \frac{3 \times 3}{2 \times 3} = \frac{9}{6}$. 5. **Compare numerators:** - $\frac{9}{6}$ and $\frac{17}{6}$ have the same denominator, so compare 9 and 17. - Since $9 < 17$, we have $\frac{9}{6} < \frac{17}{6}$. 6. **Final answer:** - $1 \frac{1}{2} = \frac{3}{2} < \frac{17}{6}$. **Answer:** $\frac{3}{2} < \frac{17}{6}$