1. **State the problem:** Simplify or analyze the expression where the denominator is a fraction containing $2y$ and $y^2$. 2. **Identify the expression:** The denominator is given as a fraction with terms $2y$ and $y^2$. This likely means the denominator is $\frac{2y}{y^2}$. 3. **Recall the rule for dividing powers:** When dividing terms with the same base, subtract the exponents: $$\frac{a^m}{a^n} = a^{m-n}$$ 4. **Apply the rule:** Simplify $$\frac{2y}{y^2} = 2 \cdot \frac{y}{y^2} = 2 \cdot y^{1-2} = 2y^{-1}$$ 5. **Rewrite with positive exponent:** $$2y^{-1} = \frac{2}{y}$$ 6. **Final answer:** The denominator simplifies to $$\frac{2}{y}$$. This means the original denominator fraction simplifies to $\frac{2}{y}$, which is easier to work with in further calculations.