1. Stating the problem: Solve for $x$ in the equation
$$\frac{6}{11} - \left(\frac{8}{5} + \frac{9}{11} - 2\right) \div \left[\frac{7}{30} - \left(\frac{2}{15} + \frac{7}{5} - \frac{6}{4}\right)\right] = \left(\frac{18}{99} + \frac{32}{132} + \frac{8}{66}\right) \div x$$
2. Simplify inside the parentheses step-by-step:
- Calculate $\frac{8}{5} + \frac{9}{11} - 2$:
$$\frac{8}{5} + \frac{9}{11} - 2 = \frac{8}{5} + \frac{9}{11} - \frac{22}{11} = \frac{8}{5} - \frac{13}{11}$$
Find common denominator $55$:
$$\frac{8}{5} = \frac{88}{55}, \quad \frac{13}{11} = \frac{65}{55}$$
So,
$$\frac{88}{55} - \frac{65}{55} = \frac{23}{55}$$
- Calculate $\frac{2}{15} + \frac{7}{5} - \frac{6}{4}$:
Convert to common denominator $60$:
$$\frac{2}{15} = \frac{8}{60}, \quad \frac{7}{5} = \frac{84}{60}, \quad \frac{6}{4} = \frac{90}{60}$$
Sum:
$$8/60 + 84/60 - 90/60 = (8 + 84 - 90)/60 = 2/60 = \frac{1}{30}$$
- Calculate $\frac{7}{30} - \frac{1}{30} = \frac{6}{30} = \frac{1}{5}$
3. Now the left side numerator:
$$\frac{6}{11} - \frac{23}{55}$$
Common denominator $55$:
$$\frac{6}{11} = \frac{30}{55}$$
So,
$$\frac{30}{55} - \frac{23}{55} = \frac{7}{55}$$
4. The left side is now:
$$\frac{7}{55} \div \frac{1}{5} = \frac{7}{55} \times 5 = \frac{35}{55} = \frac{7}{11}$$
5. Simplify the right side numerator:
$$\frac{18}{99} + \frac{32}{132} + \frac{8}{66}$$
Find common denominator $396$:
$$\frac{18}{99} = \frac{72}{396}, \quad \frac{32}{132} = \frac{96}{396}, \quad \frac{8}{66} = \frac{48}{396}$$
Sum:
$$72 + 96 + 48 = 216$$
So,
$$\frac{216}{396} = \frac{18}{33} = \frac{6}{11}$$
6. The equation is now:
$$\frac{7}{11} = \frac{6}{11} \div x = \frac{6}{11} \times \frac{1}{x} = \frac{6}{11x}$$
7. Solve for $x$:
$$\frac{7}{11} = \frac{6}{11x}$$
Multiply both sides by $11x$:
$$7x = 6$$
Divide both sides by 7:
$$x = \frac{6}{7}$$
Final answer:
$$\boxed{\frac{6}{7}}$$
Fraction Equation 44E1B1
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.