Subjects algebra

Fraction Equations 84De0A

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1. Stating the problem: Solve the equation $2 - \frac{7}{3} = \frac{5}{3} + \frac{1}{3}$. 2. Combine the fractions on the right side: $\frac{5}{3} + \frac{1}{3} = \frac{5+1}{3} = \frac{6}{3} = 2$. 3. Rewrite the equation: $2 - \frac{7}{3} = 2$. 4. Subtract 2 from both sides: $2 - \frac{7}{3} - 2 = 2 - 2$. 5. Simplify the left side: $\cancel{2} - \frac{7}{3} - \cancel{2} = 0$. 6. This reduces to $- \frac{7}{3} = 0$, which is false. 7. Therefore, the equation has no solution. --- Next, solve $8 - 3 - \frac{3}{6} = 5$. 8. Simplify the left side: $8 - 3 = 5$, so $5 - \frac{3}{6} = 5$. 9. Rewrite $\frac{3}{6}$ as $\frac{1}{2}$: $5 - \frac{1}{2} = 5$. 10. Subtract 5 from both sides: $5 - \frac{1}{2} - 5 = 5 - 5$. 11. Simplify: $\cancel{5} - \frac{1}{2} - \cancel{5} = 0$. 12. This reduces to $- \frac{1}{2} = 0$, which is false. 13. Therefore, this equation also has no solution. --- Next, simplify $(5 - 1) \left( \frac{1}{5} - \frac{1}{10} \right)$. 14. Calculate inside the parentheses: $5 - 1 = 4$. 15. Calculate the second parentheses: $\frac{1}{5} - \frac{1}{10} = \frac{2}{10} - \frac{1}{10} = \frac{1}{10}$. 16. Multiply: $4 \times \frac{1}{10} = \frac{4}{10} = \frac{2}{5}$. --- Finally, simplify $(\frac{40}{4}) (\frac{40}{5})$. 17. Simplify each fraction: $\frac{40}{4} = 10$, $\frac{40}{5} = 8$. 18. Multiply: $10 \times 8 = 80$. --- Summary: - First equation: no solution. - Second equation: no solution. - Third expression: $\frac{2}{5}$. - Fourth expression: $80$. Note: The value "A: 324" is not related to these calculations and is not part of the solved problems.