1. **State the problem:** Evaluate the expressions $\frac{5}{4^3}$ and $\left(-\frac{3}{5}\right)^2$. 2. **Evaluate the first expression:** Calculate the denominator first: $$4^3 = 4 \times 4 \times 4 = 64$$ So the expression becomes: $$\frac{5}{64}$$ 3. **Evaluate the second expression:** Square the fraction: $$\left(-\frac{3}{5}\right)^2 = \left(-\frac{3}{5}\right) \times \left(-\frac{3}{5}\right)$$ Multiply numerators and denominators: $$= \frac{(-3) \times (-3)}{5 \times 5} = \frac{9}{25}$$ 4. **Final answers:** $$\frac{5}{64} \quad \text{and} \quad \frac{9}{25}$$