1. **State the problem:** Simplify the expression $$[(-7 + \frac{12}{5}) \cdot \left(-\frac{15}{4}\right) \cdot \left(-\frac{5}{2}\right)] : \left(\frac{5}{4}\right)$$
2. **Rewrite the expression clearly:**
$$\left(-7 + \frac{12}{5}\right) \times \left(-\frac{15}{4}\right) \times \left(-\frac{5}{2}\right) \div \frac{5}{4}$$
3. **Calculate inside the parentheses:**
$$-7 + \frac{12}{5} = \frac{-35}{5} + \frac{12}{5} = \frac{-35 + 12}{5} = \frac{-23}{5}$$
4. **Substitute back:**
$$\frac{-23}{5} \times \left(-\frac{15}{4}\right) \times \left(-\frac{5}{2}\right) \div \frac{5}{4}$$
5. **Multiply the first two fractions:**
$$\frac{-23}{5} \times \left(-\frac{15}{4}\right) = \frac{-23 \times -15}{5 \times 4} = \frac{345}{20}$$
6. **Multiply the result by the third fraction:**
$$\frac{345}{20} \times \left(-\frac{5}{2}\right) = \frac{345 \times -5}{20 \times 2} = \frac{-1725}{40}$$
7. **Divide by the last fraction:**
$$\frac{-1725}{40} \div \frac{5}{4} = \frac{-1725}{40} \times \frac{4}{5} = \frac{-1725 \times 4}{40 \times 5}$$
8. **Simplify numerator and denominator:**
$$\frac{-1725 \times 4}{40 \times 5} = \frac{-6900}{200}$$
9. **Simplify the fraction by dividing numerator and denominator by 20:**
$$\frac{\cancel{-6900}^{\div 20}}{\cancel{200}^{\div 20}} = \frac{-345}{10}$$
10. **Final answer:**
$$\boxed{-\frac{345}{10}}$$ or $$-34.5$$
This is the simplified value of the given expression.
Fraction Expression B60B50
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