1. **State the problem:** Calculate the product of the fractions $\frac{28}{1}$ and $\frac{11}{14}$. 2. **Write the formula:** The product of two fractions $\frac{a}{b}$ and $\frac{c}{d}$ is given by $$\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}.$$ 3. **Apply the formula:** Here, $a=28$, $b=1$, $c=11$, and $d=14$. So, $$\frac{28}{1} \times \frac{11}{14} = \frac{28 \times 11}{1 \times 14} = \frac{308}{14}.$$ 4. **Simplify the fraction:** Divide numerator and denominator by their greatest common divisor (GCD). The GCD of 308 and 14 is 14. $$\frac{\cancel{14} \times 22}{\cancel{14} \times 1} = \frac{22}{1} = 22.$$ 5. **Final answer:** The product of $\frac{28}{1}$ and $\frac{11}{14}$ is $22$.