1. The problem asks to solve the addition and subtraction of fractions and mixed numbers. 2. Let's solve number 5: $$\frac{7}{10} + \frac{7}{8}$$ 3. To add fractions, find a common denominator. The denominators are 10 and 8. 4. The least common denominator (LCD) of 10 and 8 is 40. 5. Convert each fraction to have denominator 40: $$\frac{7}{10} = \frac{7 \times 4}{10 \times 4} = \frac{28}{40}$$ $$\frac{7}{8} = \frac{7 \times 5}{8 \times 5} = \frac{35}{40}$$ 6. Now add the fractions: $$\frac{28}{40} + \frac{35}{40} = \frac{28 + 35}{40} = \frac{63}{40}$$ 7. Convert the improper fraction to a mixed number: $$\frac{63}{40} = 1 \frac{23}{40}$$ 8. Now solve number 6: $$1 \frac{1}{3} - \frac{5}{6}$$ 9. Convert the mixed number to an improper fraction: $$1 \frac{1}{3} = \frac{3 \times 1 + 1}{3} = \frac{4}{3}$$ 10. Find the LCD of 3 and 6, which is 6. 11. Convert fractions to denominator 6: $$\frac{4}{3} = \frac{4 \times 2}{3 \times 2} = \frac{8}{6}$$ $$\frac{5}{6}$$ stays the same. 12. Subtract the fractions: $$\frac{8}{6} - \frac{5}{6} = \frac{8 - 5}{6} = \frac{3}{6}$$ 13. Simplify the fraction by canceling common factors: $$\frac{\cancel{3}}{\cancel{6}} = \frac{1}{2}$$ 14. Final answer for number 5 is $1 \frac{23}{40}$ and for number 6 is $\frac{1}{2}$.