1. **State the problem:** We want to find the percent decrease of a fraction when its numerator is increased by 20% and its denominator is increased by 50%. 2. **Set up the original fraction:** Let the original fraction be $\frac{N}{D}$. 3. **Apply the increases:** The new numerator is $N + 0.20N = 1.20N$. The new denominator is $D + 0.50D = 1.50D$. 4. **New fraction:** The new fraction is $$\frac{1.20N}{1.50D}$$ 5. **Simplify the new fraction:** $$\frac{1.20N}{1.50D} = \frac{1.20}{1.50} \times \frac{N}{D} = \frac{\cancel{1.20}}{\cancel{1.50}} \times \frac{N}{D} = \frac{4}{5} \times \frac{N}{D} = 0.8 \times \frac{N}{D}$$ 6. **Calculate the percent decrease:** The fraction changes from $\frac{N}{D}$ to $0.8 \times \frac{N}{D}$. The decrease is $$\left(1 - 0.8\right) \times 100\% = 0.2 \times 100\% = 20\%$$ **Final answer:** The fraction decreases by 20%.