1. The first problem is to express the function given by $y = \left(\frac{6}{x}\right)^2$. 2. This means $y = \frac{36}{x^2}$ because squaring the fraction squares both numerator and denominator. 3. The second expression is $2 \cdot \frac{\sqrt{2}}{\sqrt{3}} - \frac{\sqrt{6}}{3}$. 4. Simplify $2 \cdot \frac{\sqrt{2}}{\sqrt{3}}$ by rationalizing the denominator: multiply numerator and denominator by $\sqrt{3}$ to get $2 \cdot \frac{\sqrt{6}}{3} = \frac{2\sqrt{6}}{3}$. 5. Now subtract $\frac{\sqrt{6}}{3}$ from $\frac{2\sqrt{6}}{3}$: $$\frac{2\sqrt{6}}{3} - \frac{\sqrt{6}}{3} = \frac{(2-1)\sqrt{6}}{3} = \frac{\sqrt{6}}{3}.$$