1. The problem is to continue simplifying or operating with the given expressions. 2. Let's start with the first fraction: $$\frac{x^2 - 1}{x^2 - 3x}$$. 3. Factor numerator and denominator where possible: $$x^2 - 1 = (x - 1)(x + 1)$$ $$x^2 - 3x = x(x - 3)$$ 4. So the fraction becomes: $$\frac{(x - 1)(x + 1)}{x(x - 3)}$$ 5. There are no common factors to cancel, so this is the simplified form. 6. Next, the second fraction: $$\frac{x - 2}{x^2 + 2x + 5}$$. 7. The denominator is a quadratic that does not factor nicely over the reals (discriminant $= 2^2 - 4 \times 1 \times 5 = 4 - 20 = -16 < 0$), so it remains as is. 8. Therefore, the fraction is already simplified: $$\frac{x - 2}{x^2 + 2x + 5}$$ 9. If the operation is to add or subtract these fractions, we need a common denominator, which would be: $$x(x - 3)(x^2 + 2x + 5)$$ 10. However, since the user only asked to continue the operation without specifying which operation, we have simplified the fractions as much as possible. Final simplified forms: $$\frac{(x - 1)(x + 1)}{x(x - 3)}$$ and $$\frac{x - 2}{x^2 + 2x + 5}$$