1. The problem states a man spends fractions of his monthly salary on different expenses: rent, food, and books. We need to find the total fraction spent and the fraction left. 2. Given fractions spent: - Rent: $\frac{1}{4}$ - Food: $\frac{2}{5}$ - Books: $\frac{1}{6}$ 3. First, find a common denominator to add these fractions. The denominators are 4, 5, and 6. The least common denominator (LCD) is 60. 4. Convert each fraction to have denominator 60: - Rent: $\frac{1}{4} = \frac{15}{60}$ - Food: $\frac{2}{5} = \frac{24}{60}$ - Books: $\frac{1}{6} = \frac{10}{60}$ 5. Add the fractions spent: $$\frac{15}{60} + \frac{24}{60} + \frac{10}{60} = \frac{15 + 24 + 10}{60} = \frac{49}{60}$$ 6. The fraction spent is $\frac{49}{60}$. 7. The fraction left is the remainder of the salary after spending, which is: $$1 - \frac{49}{60} = \frac{60}{60} - \frac{49}{60} = \frac{11}{60}$$ 8. Final answer: - Fraction spent: $\frac{49}{60}$ - Fraction left: $\frac{11}{60}$