Subjects algebra

Fraction Subtraction 769022

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1. Problem: Subtract the fractions and reduce to the lowest terms. 2. Formula: To subtract fractions with the same denominator, subtract the numerators and keep the denominator the same: $$\frac{a}{d} - \frac{b}{d} = \frac{a-b}{d}$$ 3. Important rule: Always simplify the fraction by dividing numerator and denominator by their greatest common divisor (GCD). 4. Solve the first problem as example: $$\frac{18}{25} - \frac{9}{25} = \frac{18-9}{25} = \frac{9}{25}$$ No simplification needed since 9 and 25 have no common factors other than 1. 5. Next problem: $$\frac{15}{18} - \frac{6}{18} = \frac{15-6}{18} = \frac{9}{18}$$ Simplify by dividing numerator and denominator by 9: $$\frac{\cancel{9}}{\cancel{18}} = \frac{1}{2}$$ 6. Next: $$\frac{15}{12} - \frac{8}{12} = \frac{15-8}{12} = \frac{7}{12}$$ Already simplified. 7. Next: $$\frac{14}{10} - \frac{6}{10} = \frac{14-6}{10} = \frac{8}{10}$$ Simplify by dividing numerator and denominator by 2: $$\frac{\cancel{8}}{\cancel{10}} = \frac{4}{5}$$ 8. Next: $$\frac{15}{20} - \frac{7}{20} = \frac{15-7}{20} = \frac{8}{20}$$ Simplify by dividing numerator and denominator by 4: $$\frac{\cancel{8}}{\cancel{20}} = \frac{2}{5}$$ Final answers for the first 5 problems: 1) $\frac{9}{25}$ 2) $\frac{1}{2}$ 3) $\frac{7}{12}$ 4) $\frac{4}{5}$ 5) $\frac{2}{5}$ Due to length, only the first problem is fully solved here as per instructions.