Fraction Subtractions A17429

1. The problem is to find the result of each subtraction expression involving fractions and mixed numbers. 2. We subtract fractions by finding a common denominator and then subtracting the numerators. 3. For mixed numbers or whole numbers with fractions, convert to improper fractions if needed before subtracting. 4. Simplify the result if possible. Now, let's solve each expression step-by-step: - $\frac{18}{25} - \frac{9}{25} = \frac{18-9}{25} = \frac{9}{25}$ - $\frac{15}{18} - \frac{6}{18} = \frac{15-6}{18} = \frac{9}{18} = \frac{1}{2}$ - $\frac{15}{12} - \frac{8}{12} = \frac{15-8}{12} = \frac{7}{12}$ - $\frac{14}{10} - \frac{6}{10} = \frac{14-6}{10} = \frac{8}{10} = \frac{4}{5}$ - $\frac{15}{20} - \frac{7}{20} = \frac{15-7}{20} = \frac{8}{20} = \frac{2}{5}$ - $\frac{13}{15} - \frac{4}{15} = \frac{13-4}{15} = \frac{9}{15} = \frac{3}{5}$ - $\frac{6}{7} - \frac{2}{7} = \frac{6-2}{7} = \frac{4}{7}$ - $\frac{16}{17} - \frac{10}{17} = \frac{16-10}{17} = \frac{6}{17}$ - $7 - \frac{3}{6}/10$ (assuming $\frac{3}{6}/10 = \frac{3}{6} \div 10 = \frac{3}{6} \times \frac{1}{10} = \frac{3}{60} = \frac{1}{20}$) so $7 - \frac{1}{20} = \frac{140}{20} - \frac{1}{20} = \frac{139}{20}$ - $\frac{10}{12} - \frac{8}{12} = \frac{10-8}{12} = \frac{2}{12} = \frac{1}{6}$ - $\frac{8}{14} - \frac{6}{14} = \frac{8-6}{14} = \frac{2}{14} = \frac{1}{7}$ - $\frac{12}{25} - \frac{7}{25} = \frac{12-7}{25} = \frac{5}{25} = \frac{1}{5}$ - $\frac{9}{8} - \frac{5}{8} = \frac{9-5}{8} = \frac{4}{8} = \frac{1}{2}$ - $\frac{18}{24} - \frac{10}{24} = \frac{18-10}{24} = \frac{8}{24} = \frac{1}{3}$ - $\frac{15}{16} - \frac{7}{16} = \frac{15-7}{16} = \frac{8}{16} = \frac{1}{2}$ - $\frac{3}{9} - \frac{7}{9} - \frac{1}{9} = \frac{3-7-1}{9} = \frac{-5}{9}$ - $\frac{10}{8} - \frac{1}{5} - \frac{5}{8} = \frac{10}{8} - \frac{5}{8} - \frac{1}{5} = \frac{5}{8} - \frac{1}{5} = \frac{25}{40} - \frac{8}{40} = \frac{17}{40}$ - $\frac{7}{4} - \frac{3}{6} - \frac{1}{4} = \frac{7}{4} - \frac{1}{2} - \frac{1}{4} = \frac{7}{4} - \frac{2}{4} - \frac{1}{4} = \frac{4}{4} = 1$ - $\frac{5}{8} - \frac{1}{2} - \frac{5}{8} = \frac{5}{8} - \frac{4}{8} - \frac{5}{8} = \frac{5-4-5}{8} = \frac{-4}{8} = -\frac{1}{2}$ - $7 - \frac{6}{3} - \frac{2}{3} = 7 - 2 - \frac{2}{3} = 5 - \frac{2}{3} = \frac{15}{3} - \frac{2}{3} = \frac{13}{3}$ - $\frac{9}{5} - \frac{2}{6} - \frac{4}{2} = \frac{9}{5} - \frac{1}{3} - 2 = \frac{9}{5} - \frac{1}{3} - \frac{10}{5} = \frac{9-10}{5} - \frac{1}{3} = -\frac{1}{5} - \frac{1}{3} = -\frac{3}{15} - \frac{5}{15} = -\frac{8}{15}$ - $\frac{2}{7} - \frac{1}{3} - \frac{6}{3} = \frac{2}{7} - \frac{1}{3} - 2 = \frac{2}{7} - \frac{1}{3} - \frac{14}{7} = \frac{2-14}{7} - \frac{1}{3} = -\frac{12}{7} - \frac{1}{3} = -\frac{36}{21} - \frac{7}{21} = -\frac{43}{21}$ - $\frac{2}{5} - 1 - 1 = \frac{2}{5} - 2 = \frac{2}{5} - \frac{10}{5} = -\frac{8}{5}$ - $\frac{2}{9} - \frac{1}{7} - 1 = \frac{2}{9} - \frac{1}{7} - \frac{9}{9} = \frac{2-9}{9} - \frac{1}{7} = -\frac{7}{9} - \frac{1}{7} = -\frac{49}{63} - \frac{9}{63} = -\frac{58}{63}$ - $\frac{1}{6} - \frac{4}{5} - \frac{3}{4} = \frac{1}{6} - \frac{4}{5} - \frac{3}{4} = \frac{10}{60} - \frac{48}{60} - \frac{45}{60} = \frac{10-48-45}{60} = -\frac{83}{60}$ - $\frac{8}{2} - \frac{5}{4} - \frac{4}{5} = 4 - \frac{5}{4} - \frac{4}{5} = \frac{20}{5} - \frac{5}{4} - \frac{4}{5} = \frac{80}{20} - \frac{25}{20} - \frac{16}{20} = \frac{80-25-16}{20} = \frac{39}{20}$ - $6 - \frac{4}{3} - \frac{2}{5} = 6 - \frac{4}{3} - \frac{2}{5} = \frac{90}{15} - \frac{20}{15} - \frac{6}{15} = \frac{90-20-6}{15} = \frac{64}{15}$ - $\frac{9}{3} - \frac{5}{4} - \frac{1}{4} = 3 - \frac{6}{4} = 3 - \frac{3}{2} = \frac{6}{2} - \frac{3}{2} = \frac{3}{2}$ - $\frac{4}{10} - \frac{1}{9} - 0 = \frac{4}{10} - \frac{1}{9} = \frac{18}{45} - \frac{5}{45} = \frac{13}{45}$ - $\frac{5}{8} - \frac{5}{3} - \frac{5}{8} = \frac{5}{8} - \frac{5}{8} - \frac{5}{3} = 0 - \frac{5}{3} = -\frac{5}{3}$ - $\frac{7}{6} - \frac{5}{2} - \frac{2}{6} = \frac{7}{6} - \frac{15}{6} - \frac{2}{6} = \frac{7-15-2}{6} = -\frac{10}{6} = -\frac{5}{3}$ - $10 - 4 - 2 = 4$ - $\frac{4}{5} - \frac{2}{5} - \frac{4}{5} = \frac{4-2-4}{5} = -\frac{2}{5}$ - $\frac{8}{9} - 4 - \frac{5}{9} = \frac{8}{9} - \frac{36}{9} - \frac{5}{9} = \frac{8-36-5}{9} = -\frac{33}{9} = -\frac{11}{3}$ - $3 - \frac{1}{7} - \frac{6}{7} = 3 - 1 = 2$ - $\frac{2}{13} - \frac{1}{10} - \frac{10}{13} = \frac{2-10}{13} - \frac{1}{10} = -\frac{8}{13} - \frac{1}{10} = -\frac{80}{130} - \frac{13}{130} = -\frac{93}{130}$ - $\frac{1}{2} - \frac{2}{11} - \frac{4}{11} = \frac{1}{2} - \frac{6}{11} = \frac{11}{22} - \frac{12}{22} = -\frac{1}{22}$ - $\frac{5}{3} - 2 - \frac{1}{8} = \frac{5}{3} - \frac{16}{8} - \frac{1}{8} = \frac{5}{3} - \frac{17}{8} = \frac{40}{24} - \frac{51}{24} = -\frac{11}{24}$ - $\frac{4}{6} - 5 - \frac{3}{6} = \frac{2}{3} - 5 - \frac{1}{2} = \frac{4}{6} - \frac{30}{6} - \frac{3}{6} = \frac{4-30-3}{6} = -\frac{29}{6}$ - $\frac{9}{10} - \frac{4}{10} - 1 = \frac{5}{10} - 1 = \frac{1}{2} - 1 = -\frac{1}{2}$ - $\frac{9}{10} - \frac{8}{10} - \frac{1}{8} = \frac{1}{10} - \frac{1}{8} = \frac{4}{40} - \frac{5}{40} = -\frac{1}{40}$ - $3 - 1 - \frac{4}{5} = 2 - \frac{4}{5} = \frac{10}{5} - \frac{4}{5} = \frac{6}{5}$ - $9 - 1 - \frac{12}{13} = 8 - \frac{12}{13} = \frac{104}{13} - \frac{12}{13} = \frac{92}{13}$ - $\frac{7}{8} - \frac{5}{12} - \frac{5}{12} = \frac{7}{8} - \frac{10}{12} = \frac{21}{24} - \frac{20}{24} = \frac{1}{24}$ - $3 - \frac{4}{6} - \frac{5}{6} = 3 - \frac{9}{6} = 3 - \frac{3}{2} = \frac{6}{2} - \frac{3}{2} = \frac{3}{2}$ - $\frac{3}{16} - \frac{1}{9} - \frac{6}{16} = \frac{3-6}{16} - \frac{1}{9} = -\frac{3}{16} - \frac{1}{9} = -\frac{27}{144} - \frac{16}{144} = -\frac{43}{144}$ - $\frac{7}{12} - \frac{5}{12} - \frac{1}{6} = \frac{2}{12} - \frac{1}{6} = \frac{1}{6} - \frac{1}{6} = 0$ - $\frac{13}{22} - \frac{2}{22} - \frac{2}{22} = \frac{13-2-2}{22} = \frac{9}{22}$ - $\frac{7}{4} - \frac{1}{4} - \frac{3}{4} = \frac{7-1-3}{4} = \frac{3}{4}$ - $8 - 1 - 1 = 6$ Final answers are as above for each expression.