1. The problem appears to involve comparing or calculating values related to fractions and given options A, B, C, D. 2. Let's clarify the fractions: $\frac{2}{5}$ and $\frac{2}{3}$, and the numbers 1 and 51. 3. Since the question is unclear, let's assume it asks to find the sum or product of the fractions and numbers or to compare them. 4. Calculate the sum of $\frac{2}{5}$ and $\frac{2}{3}$: $$\frac{2}{5} + \frac{2}{3} = \frac{2 \times 3}{5 \times 3} + \frac{2 \times 5}{3 \times 5} = \frac{6}{15} + \frac{10}{15} = \frac{16}{15} = 1 \frac{1}{15}$$ 5. If we add 1 and 51 to this sum: $$1 + 51 + 1 \frac{1}{15} = 52 + 1 \frac{1}{15} = 53 \frac{1}{15} = \frac{796}{15}$$ 6. None of the options A (31), B (62), C (93), D (155) match this result. 7. Alternatively, if the problem is to multiply $\frac{2}{5}$ and $\frac{2}{3}$: $$\frac{2}{5} \times \frac{2}{3} = \frac{4}{15}$$ 8. Multiplying by 51: $$\frac{4}{15} \times 51 = \frac{4 \times 51}{15} = \frac{204}{15} = 13 \frac{9}{15} = 13 \frac{3}{5} = 13.6$$ 9. This also does not match any options. 10. Without further clarification, the best interpretation is the sum of the fractions $\frac{2}{5} + \frac{2}{3} = \frac{16}{15}$ or approximately 1.0667. Final answer: $\frac{16}{15}$ or approximately 1.07.