Subjects algebra

Fraction Value 48E247

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Let's start with what we know: $a - b = 2$ $b - c = 2$ Now, find $a - c$: $a - c = (a - b) + (b - c) = 2 + 2 = 4$ Next, find the numerator: $(a - b)^2 + (b - c)^2 = 2^2 + 2^2 = 4 + 4 = 8$ Find the denominator: $(a - c)^2 = 4^2 = 16$ Now, put it all together: $\frac{(a - b)^2 + (b - c)^2}{(a - c)^2} = \frac{8}{16} = \frac{1}{2}$ So, the answer is $\frac{1}{2}$! Great job!