1. **State the problem:** We have two functions $f(x) = 4^x$ and $g(x) = 4^{\frac{1}{2}x}$ with a table of values for $x$ from $-2$ to $2$. Some values of $g(x)$ are missing and labeled as $A$, $B$, and $C$. We need to find these missing values. 2. **Recall the function definitions:** - $f(x) = 4^x$ - $g(x) = 4^{\frac{1}{2}x} = (4^{\frac{1}{2}})^x = 2^x$ since $4^{\frac{1}{2}} = 2$ 3. **Calculate $A = g(-2)$:** $$g(-2) = 4^{\frac{1}{2} \times (-2)} = 4^{-1} = \frac{1}{4}$$ 4. **Calculate $B = g(0)$:** $$g(0) = 4^{\frac{1}{2} \times 0} = 4^0 = 1$$ 5. **Calculate $C = g(2)$:** $$g(2) = 4^{\frac{1}{2} \times 2} = 4^1 = 4$$ 6. **Summary of missing values:** - $A = \frac{1}{4}$ - $B = 1$ - $C = 4$ These values match the pattern of $g(x) = 2^x$ evaluated at the respective $x$ values. **Final answers:** $$A = \frac{1}{4}, \quad B = 1, \quad C = 4$$