1. **Problem statement:** We are given a bar graph showing the number of fruits sold in a school's cafeteria for four types of fruits: Oranges, Portugals, Bananas, and Mangoes. - Number of Portugals sold = 96 - Number of Mangoes sold = $\frac{1}{3}$ the number of Portugals - Mean number of fruits sold = 60 We need to find the number of Bananas sold and draw the bar accordingly. 2. **Step 1: Calculate the number of Mangoes sold.** $$\text{Mangoes} = \frac{1}{3} \times 96 = 32$$ 3. **Step 2: Use the mean to find the total number of fruits sold.** Mean number of fruits sold = 60 for 4 fruit types, so total fruits sold: $$\text{Total} = 60 \times 4 = 240$$ 4. **Step 3: Use the total to find the number of Bananas sold.** Let $B$ be the number of Bananas sold. We know: $$\text{Oranges} + \text{Portugals} + B + \text{Mangoes} = 240$$ From the graph, Oranges sold = 40, Portugals = 96, Mangoes = 32. Substitute: $$40 + 96 + B + 32 = 240$$ Simplify: $$168 + B = 240$$ 5. **Step 4: Solve for $B$.** $$B = 240 - 168 = 72$$ 6. **Answer:** The number of Bananas sold is **72**. This means the bar for Bananas should reach 72 on the graph's y-axis.