Subjects algebra

Fuel Efficiency 3Ad8C2

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1. The problem asks us to complete the table by calculating the fuel efficiency in litres per kilometre (L/km) for each car. 2. The formula to calculate fuel efficiency is: $$\text{L/km} = \frac{\text{Litres used}}{\text{Distance travelled (km)}}$$ This means we divide the amount of fuel used by the distance the car traveled to find how many litres are used per kilometre. 3. Calculate L/km for each car: - Falcador: $$\frac{12.342}{36.3} = 0.3401$$ - Canyonero: $$\frac{14.415}{46.5} = 0.3100$$ - Magnum: $$\frac{9.405}{28.5} = 0.3302$$ - Minima: $$\frac{19.734}{50.6} = 0.3901$$ 4. Interpretation: The lower the L/km value, the more fuel efficient the car is because it uses fewer litres per kilometre. 5. Final completed table values for L/km: - Falcador: 0.3401 - Canyonero: 0.3100 - Magnum: 0.3302 - Minima: 0.3901 Therefore, Canyonero is the most fuel efficient car among the four.