1. **State the problem:** We analyze the function's domain, range, intercepts, and asymptotes based on the graph description. 2. **Domain:** The function has a vertical asymptote near $x=1$, so the domain excludes $x=1$. Thus, the domain is $$(-\infty,1) \cup (1,\infty).$$ 3. **Range:** The horizontal asymptote is near $y=3$, and the function approaches it from above and below, so the range excludes $y=3$. The function appears to cover all other $y$ values, so the range is $$(-\infty,3) \cup (3,\infty).$$ 4. **x-intercepts:** The graph crosses the $x$-axis where $y=0$. From the description, the curve crosses the $x$-axis twice (two branches). Let these intercepts be at $x=a$ and $x=b$ (exact values not given). So, $x=a$ and $x=b$ are the x-intercepts. 5. **y-intercept:** The y-intercept is where $x=0$. The graph crosses the y-axis at some $y=c$ (exact value not given). So, $y=c$ is the y-intercept. 6. **Horizontal asymptotes:** The blue dashed line is a horizontal asymptote near $y=3$, so $$y=3$$ is the horizontal asymptote. 7. **Vertical asymptotes:** The red curve has a vertical asymptote near $x=1$, so $$x=1$$ is the vertical asymptote. 8. **Oblique asymptotes:** The graph has a slanted (oblique) asymptote crossing near $y=3$ and $x\approx -2$. The equation of the oblique asymptote is a line with negative slope passing near these points. Without exact formula, we denote it as $$y=mx+b$$ with $m<0$. Since the horizontal asymptote is $y=3$, the oblique asymptote is likely the blue dashed line described as decreasing and crossing near $y=3$ and $x\approx -2$. **Summary:** - Domain: $$(-\infty,1) \cup (1,\infty)$$ - Range: $$(-\infty,3) \cup (3,\infty)$$ - x-intercepts: $$x=a, x=b$$ (two values) - y-intercept: $$y=c$$ - Horizontal asymptote: $$y=3$$ - Vertical asymptote: $$x=1$$ - Oblique asymptote: $$y=mx+b$$ (decreasing line crossing near $y=3$, $x\approx -2$) Since exact intercept values and oblique asymptote equation are not provided, we describe them qualitatively.