1. **State the problem:** We need to find the value of $f(-2 - g(3))$ given the functions $f(x) = \frac{3}{4}x + 10$ and $g(x) = x^2 - 3$. 2. **Calculate $g(3)$:** Substitute $x=3$ into $g(x)$: $$g(3) = 3^2 - 3 = 9 - 3 = 6$$ 3. **Evaluate the expression inside $f$:** $$-2 - g(3) = -2 - 6 = -8$$ 4. **Calculate $f(-8)$:** Substitute $x = -8$ into $f(x)$: $$f(-8) = \frac{3}{4}(-8) + 10$$ 5. **Simplify the multiplication:** $$\frac{3}{4} \times (-8) = \frac{3 \times (-8)}{4}$$ $$= \frac{\cancel{3} \times (-8)}{\cancel{4}}$$ $$= -6$$ 6. **Add 10:** $$f(-8) = -6 + 10 = 4$$ **Final answer:** $$f(-2 - g(3)) = 4$$