1. We are given two functions: $$f(x) = \frac{3}{4}x + 10$$ and $$g(x) = x^2 - 3$$. We need to find the value of $$f(-2 - g(3))$$. 2. First, calculate $$g(3)$$ by substituting $$x = 3$$ into $$g(x)$$: $$g(3) = 3^2 - 3 = 9 - 3 = 6$$. 3. Next, evaluate the expression inside the function $$f$$: $$-2 - g(3) = -2 - 6 = -8$$. 4. Now, substitute $$x = -8$$ into $$f(x)$$: $$f(-8) = \frac{3}{4}(-8) + 10 = -6 + 10 = 4$$. 5. Therefore, the value of $$f(-2 - g(3))$$ is $$4$$.