1. The problem asks to find the value of the function $f(x) = \frac{2}{x^2}$ at $x = -5$. 2. The formula for $f(x)$ is given as: $$f(x) = \frac{2}{x^2}$$ 3. To find $f(-5)$, substitute $x = -5$ into the formula: $$f(-5) = \frac{2}{(-5)^2}$$ 4. Calculate the square of $-5$: $$(-5)^2 = 25$$ 5. Substitute back: $$f(-5) = \frac{2}{25}$$ 6. This fraction cannot be simplified further, so the final answer is: $$f(-5) = \frac{2}{25}$$ This means when $x$ is $-5$, the value of $f(x)$ is $\frac{2}{25}$.