Question: Practice Quiz: Operations on Functions [WA-21] Algebra I Semester 1 / Section 4 - Introduction to Functions 4. Find $f(-8)$ when $f(x) = -2x+3$. f(-8) = 5 f(-8) = 19 f(-8) = -40 f(-8) = 40 5. Find $f(1)$ when $f(x) = 4x - 10$. f(1) = \frac{1}{2} f(1) = 4 f(1) = 6 f(1) = -6 6. Which of the following ordered pairs is a solution to $f(x) = \frac{1}{2} x - 8$ ? (4, -4)

1. **Problem 4:** Find $f(-8)$ when $f(x) = -2x + 3$. 2. **Formula:** To find $f(a)$, substitute $x = a$ into the function: $$f(a) = -2a + 3$$ 3. **Calculation:** Substitute $x = -8$: $$f(-8) = -2(-8) + 3 = 16 + 3 = 19$$ 4. **Answer:** $f(-8) = 19$ --- 5. **Problem 5:** Find $f(1)$ when $f(x) = 4x - 10$. 6. **Formula:** Substitute $x = 1$: $$f(1) = 4(1) - 10 = 4 - 10 = -6$$ 7. **Answer:** $f(1) = -6$ --- 8. **Problem 6:** Check if the ordered pair $(4, -4)$ is a solution to $f(x) = \frac{1}{2}x - 8$. 9. **Formula:** Substitute $x = 4$ and check if $f(4) = -4$: $$f(4) = \frac{1}{2} \times 4 - 8 = 2 - 8 = -6$$ 10. Since $f(4) = -6 \neq -4$, the pair $(4, -4)$ is **not** a solution. --- **Final answers:** - Problem 4: $19$ - Problem 5: $-6$ - Problem 6: $(4, -4)$ is not a solution.