1. The problem asks to sketch the curve of a function $f(x)$ and its inverse $f^{-1}(x)$ on the same Cartesian plane, along with the first bisector line $y=x$. 2. We are given tables of coordinates for $f(x)$ and $f^{-1}(x)$: For $f(x)$: $$\begin{array}{c|ccccccccccc} x & -2 & -1.6 & -1.2 & -0.8 & -0.4 & 0 & 0.4 & 0.8 & 1.2 & 1.6 & 2 \\ y & 0.1 & 0.2 & 0.3 & 0.4 & 0.6 & 1.0 & 1.6 & 2.4 & 3.7 & 5.8 & 9.0 \\\end{array}$$ For $f^{-1}(x)$: $$\begin{array}{c|ccccccccccc} x & 0.1 & 0.2 & 0.3 & 0.4 & 0.6 & 1.0 & 1.6 & 2.4 & 3.7 & 5.8 & 9.0 \\ y & -2 & -1.6 & -1.2 & -0.8 & -0.4 & 0 & 0.4 & 0.8 & 1.2 & 1.6 & 2 \\\end{array}$$ 3. The inverse function $f^{-1}(x)$ swaps the roles of $x$ and $y$ from $f(x)$, which is consistent with the tables. 4. The first bisector line $y=x$ is the line where the function and its inverse intersect. 5. To sketch: - Plot the points of $f(x)$ from the first table. - Plot the points of $f^{-1}(x)$ from the second table. - Draw the line $y=x$. 6. The curve of $f^{-1}(x)$ is the reflection of $f(x)$ about the line $y=x$. 7. This visualization helps understand the relationship between a function and its inverse. Final answer: The function $f(x)$ and its inverse $f^{-1}(x)$ are plotted using the given points, and the first bisector $y=x$ is included to show their symmetry.