1. The problem asks us to find where the function $f(x)$ is less than zero, i.e., where $f(x)<0$. 2. From the graph description, $f(x)$ has a peak around $x=-4$, a trough near $x=2$, and crosses the y-axis near $y=0$. 3. To determine where $f(x)<0$, we look for intervals where the graph is below the x-axis (where $y<0$). 4. The graph crosses the x-axis near $x=0$ (since it crosses the y-axis near $y=0$), so the sign of $f(x)$ changes around this point. 5. Since the peak at $x=-4$ is above the x-axis and the trough at $x=2$ is below, the function is positive for $x$ less than approximately 0 and negative for $x$ greater than approximately 0. 6. Therefore, the solution is: $$f(x)<0 \text{ for } x > 0$$ 7. In plain language, the function is negative for all $x$ values greater than zero, meaning the graph lies below the x-axis to the right of zero.