1. The problem states that the point $(3, -5)$ lies on the graph of $y = f(x)$. 2. We need to find which point lies on the graph of $y = f(x + 3)$. 3. Recall the transformation rule: For $y = f(x + c)$, the graph of $f(x)$ shifts horizontally to the left by $c$ units. 4. To find the corresponding point on $y = f(x + 3)$, we set $x + 3 = 3$ (the original $x$-value) because the function input is shifted. 5. Solving for $x$, we get: $$x + 3 = 3$$ $$\cancel{x + 3} = \cancel{3}$$ $$x = 0$$ 6. The $y$-value remains the same, so the point on $y = f(x + 3)$ is $(0, -5)$. 7. Checking the options, $(0, -5)$ is the correct point on the graph of $y = f(x + 3)$. Final answer: $(0, -5)$